Re: Freeze Protection for greenhouses

Brett Lymn (blymn@awadi.com.au)
Mon, 26 Feb 1996 15:32:41 +1030 (CST)

According to Randy Lamb:
>
>
>I don't have be old physics text book handy but if I recall correctly, to
>cool 1 millilitre of water by 1 degree Ceslius, it requires the removal of 1
>calorie of energy. A Litre would then require 1000 calories to cool it only
>1 degree. For a gallon, well, I need a conversion calculator for that one.
>

Me too - the latent heat of crystalisation of water is 80kcal per
litre (assuming pure water). So to freeze one litre of water that was
at 3 deg C you need 83kcal - multiply this number by the number of
litres in 50 gallons.....

-- Brett Lymn, Computer Systems Administrator, AWA Defence Industries
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