Re: Celcius to Farenheight and vice versa

From: Paul Burkhardt (burkhard@aries.scs.uiuc.edu)
Date: Wed Apr 22 1998 - 09:20:08 PDT

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Date: Wed, 22 Apr 1998 11:20:08 -0500 (CDT)
From: Paul Burkhardt <burkhard@aries.scs.uiuc.edu>
To: cp@opus.hpl.hp.com
Message-Id: <aabcdefg1345$foo@default>
Subject: Re: Celcius to Farenheight and vice versa

Hi Carl,

> OK, being in Canada and using the metric system, I have a simple rule for
> converting C to F. Double it and add Thirty. So if the temp is 5C then
> 5+5=10 + 30 = about 40F, example 2. 20C = 20+20+30= about 70F.

That's nice way to approximate, and easy to remember. :) Good thinking,
9/5 is indeed close to a factor of two, and you offset the extra
multiple fraction by adding less than 32. I'll use this method as it's
fast and close to the true value.

Paul Burkhardt

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